SL Paper 3

The circuit shown may be used to measure the internal resistance of a cell.

M17/4/PHYSI/SP3/ENG/TZ2/02

The ammeter used in the experiment in (b) is an analogue meter. The student takes measurements without checking for a “zero error” on the ammeter.

An ammeter and a voltmeter are connected in the circuit. Label the ammeter with the letter A and the voltmeter with the letter V.

[1]
a.

In one experiment a student obtains the following graph showing the variation with current I of the potential difference V across the cell.

M17/4/PHYSI/SP3/ENG/TZ2/02b

Using the graph, determine the best estimate of the internal resistance of the cell.

[3]
b.

State what is meant by a zero error.

[1]
c.i.

After taking measurements the student observes that the ammeter has a positive zero error. Explain what effect, if any, this zero error will have on the calculated value of the internal resistance in (b).

[2]
c.ii.

Markscheme

correct labelling of both instruments

 

[1 mark]

a.

V = E – Ir

large triangle to find gradient and correct read-offs from the line
OR
use of intercept E = 1.5 V and another correct data point

internal resistance = 0.60 Ω

For MP1 – do not award if only \(R = \frac{V}{I}\) is used.

For MP2 points at least 1A apart must be used.

For MP3 accept final answers in the range of 0.55 Ω to 0.65 Ω.

[3 marks]

b.

a non-zero reading when a zero reading is expected/no current is flowing
OR
a calibration error

 

OWTTE
Do not accept just “systematic error”.

[1 mark]

c.i.

the error causes «all» measurements to be high/different/incorrect

effect on calculations/gradient will cancel out
OR
effect is that value for r is unchanged

Award [1 max] for statement of “no effect” without valid argument.

OWTTE

[2 marks]

c.ii.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.i.
[N/A]
c.ii.



An electrical circuit is used during an experiment to measure the current I in a variable resistor of resistance R. The emf of the cell is e and the cell has an internal resistance r.

A graph shows the variation of \(\frac{1}{I}\) with R.

Show that the gradient of the graph is equal to \(\frac{1}{e}\).

[2]
a.

State the value of the intercept on the R axis.

[1]
b.

Markscheme

«ε = IR + Ir»

\(\frac{1}{I} = \frac{R}{\varepsilon } + \frac{r}{\varepsilon }\)

identifies equation with y = mx + c

«hence m = \(\frac{1}{\varepsilon }\)»

No mark for stating data booklet equation

Do not accept working where r is ignored or ε = IR is used

OWTTE

a.

«–» r

Allow answer in words

b.

Examiners report

[N/A]
a.
[N/A]
b.